Newton's Laws as Axioms and Inertial Frames
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You should be comfortable with vector calculus, specifically derivatives of position vectors, and the basic definitions of displacement, velocity, and acceleration from the previous lecture.
Why this matters
Newton's laws are not merely empirical rules; they are the foundational axioms that define the structure of classical space and time.
While kinematics describes how objects move, dynamics explains why they move that way. However, before we can apply Newton's second law, we must establish the stage upon which the drama unfolds: the inertial frame. Without a rigorous definition of what constitutes a "valid" reference frame, the equation \(\mathbf{F} = m\mathbf{a}\) is ambiguous, as acceleration is not an absolute quantity but depends on the observer's state of motion. This lecture bridges the gap between descriptive kinematics and predictive dynamics by identifying the specific class of frames in which the laws of physics take their simplest form.
The Problem of the Observer
Imagine you are sitting in a train moving at a constant speed. If you toss a ball straight up, it lands back in your hand. To you, the ball moves in a vertical line. To a person standing on the platform, the ball follows a parabolic arc. Both descriptions are correct, yet they look different. This raises a fundamental question: which observer is "right"? In Newtonian mechanics, there is no single privileged observer. Instead, we define a special class of observers, called inertial frames, in which the laws of motion are simplest. In these frames, an object with no net force acting on it continues in a straight line at constant speed. If you are in a frame where a force-free object accelerates, your frame is not inertial; it is accelerating relative to the true inertial class. The core task of this lecture is to define this class mathematically and to show that Newton's laws are invariant under transformations between any two such frames.
Defining the Inertial Class
An inertial frame is not defined by what it contains, but by how it moves relative to other frames. We postulate that if one frame is inertial, then any other frame moving at a constant velocity relative to it is also inertial. This set of all such frames forms the "inertial class." Mathematically, the transformation between two inertial frames \(S\) and \(S'\) is a Galilean transformation. It consists of a spatial translation \(\mathbf{d}\), a fixed rotation \(R\), and a constant velocity boost \(\mathbf{V}\). Crucially, time is absolute: \(t' = t\). Because the relative velocity \(\mathbf{V}\) is constant, the relative acceleration is zero. This zero relative acceleration is the key property that preserves the form of Newton's second law.
Here, \(\mathbf{r}(t)\) is the position in frame \(S\), and \(\mathbf{r}'(t)\) is the position in frame \(S'\). The rotation \(R\) is time-independent, meaning the axes of \(S'\) do not rotate relative to \(S\). This restriction is vital; if the axes were rotating, fictitious forces would appear, violating the simple form of \(\mathbf{F} = m\mathbf{a}\).
Galilean Invariance of the Second Law
We now demonstrate that Newton's second law is invariant under these transformations. Let us differentiate the position transformation twice with respect to time. Since \(\mathbf{d}\) is constant and \(R\) is fixed, their derivatives vanish. The first derivative gives the velocity relation: \(\mathbf{v}' = R\mathbf{v} + \mathbf{V}\). The second derivative gives the acceleration relation: \(\mathbf{a}' = R\mathbf{a}\). This result shows that acceleration transforms as a vector under rotations but is unaffected by the constant velocity boost \(\mathbf{V}\). This is the mathematical heart of Galilean relativity: uniform motion is indistinguishable from rest when measuring acceleration.
Now consider the force. In Newtonian mechanics, forces are typically functions of relative positions and relative velocities (e.g., gravity depends on \(\mathbf{r}_1 - \mathbf{r}_2\), and drag depends on \(\mathbf{v}_1 - \mathbf{v}_2\)). Under a Galilean transformation, relative positions rotate by \(R\), and relative velocities also rotate by \(R\) (since the constant \(\mathbf{V}\) cancels out in the difference \(\mathbf{v}_1' - \mathbf{v}_2' = R(\mathbf{v}_1 - \mathbf{v}_2)\)). Therefore, the force vector transforms as \(\mathbf{F}' = R\mathbf{F}\). Substituting these into Newton's second law in the primed frame:
Since \(R\) is a linear operator, we can factor it out: \(R(\mathbf{F} - m\mathbf{a}) = 0\). Because \(R\) is a rotation matrix (and thus invertible), this implies \(\mathbf{F} - m\mathbf{a} = 0\), or \(\mathbf{F} = m\mathbf{a}\). Thus, if the law holds in one inertial frame, it holds in all inertial frames. This is the content of derivation D-021.
The Role of Mass and Force
The invariance argument above relies on two assumptions: that mass \(m\) is invariant (the same in all inertial frames) and that forces are constructed from relative quantities. Mass invariance is a postulate of Newtonian mechanics; it is not derived from the laws themselves but is required for consistency. If mass varied with velocity, the simple form of the second law would break down under boosts. Similarly, the definition of force as a function of relative state variables ensures that the "interaction" between two particles looks the same to all inertial observers. If a force depended on a velocity measured relative to “absolute space” rather than relative to other bodies (such as the air for drag), different inertial observers would assign it different values and predict different accelerations, violating the principle of relativity. Therefore, the structure of Newtonian dynamics is tightly coupled to the definition of the inertial frame.
The derivation
Galilean Invariance of Newton's Laws
Under a Galilean transformation between two frames — a constant spatial translation \(\mathbf{d}\), a fixed rotation \(R\in SO(3)\), and a constant-velocity boost \(\mathbf{V}\), with absolute time \(t'=t\) — Newton's second law \(\mathbf{F}=m\mathbf{a}\) keeps exactly the same algebraic form, provided the force transforms as a vector built from relative positions and relative velocities. The transformations that leave the law form-invariant are precisely those with zero relative acceleration; these define the inertial class of frames.
A common misconception is that the Earth is an inertial frame. While it is a good approximation for many laboratory experiments, the Earth rotates and orbits the Sun. These accelerations introduce small fictitious forces (Coriolis and centrifugal) that are detectable in precision experiments, such as the Foucault pendulum. Strictly speaking, the Earth is a non-inertial frame, and Newton's second law in its simple form \(\mathbf{F} = m\mathbf{a}\) is only approximately valid on its surface. C
Worked example
Problem. A particle of mass \(m = 2.0\ \mathrm{kg}\) is subjected to a constant force \(\mathbf{F} = (3.0\ \mathrm{N})\hat{\mathbf{i}} + (4.0\ \mathrm{N})\hat{\mathbf{j}}\) in an inertial frame \(S\). Frame \(S'\) moves with a constant velocity \(\mathbf{V} = (5.0\ \mathrm{m/s})\hat{\mathbf{i}}\) relative to \(S\). Calculate the acceleration of the particle as measured in frame \(S'\).
- Calculate the acceleration in frame \(S\) using Newton's second law: \(\mathbf{a} = \mathbf{F}/m\).
- Apply the Galilean transformation for acceleration: \(\mathbf{a}' = \mathbf{a}\) (since \(\mathbf{V}\) is constant, its derivative is zero).
- Verify the result by checking the invariance of the force and mass.
Units check. Force is in Newtons (\(\mathrm{kg \cdot m/s^2}\)), mass is in kilograms (\(\mathrm{kg}\)). Dividing \(\mathrm{kg \cdot m/s^2}\) by \(\mathrm{kg}\) yields \(\mathrm{m/s^2}\), which is the correct unit for acceleration. The velocity of the frame \(S'\) is in \(\mathrm{m/s}\), but since it is constant, it does not contribute to the acceleration term.
Three quick tests
- Why must the rotation matrix \(R\) in a Galilean transformation be time-independent?
Answer
If \(R\) depended on time, the second derivative of the position would include terms involving \(\dot{R}\) and \(\ddot{R}\), leading to fictitious forces that are not present in the original frame, thus breaking the invariance of Newton's second law. - Can a frame moving with constant acceleration relative to an inertial frame be considered inertial?
Answer
No. A frame with constant acceleration relative to an inertial frame is non-inertial. Observers in such a frame would perceive a uniform fictitious force acting on all masses, which cannot be transformed away by a Galilean transformation. - What happens to the relative velocity of two particles under a Galilean boost?
Answer
The relative velocity transforms by the rotation matrix \(R\), but its magnitude remains invariant. The constant boost velocity \(\mathbf{V}\) cancels out when taking the difference between the two particles' velocities.
Problem set for PU-101 →
Each derivation in this unit ends with five graded problems with full solutions.
Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.