Magnetized Matter, Bound Currents and H
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You should be comfortable with the vector identity \(\nabla \cdot (\vec{A} \times \vec{B}) = \vec{B} \cdot (\nabla \times \vec{A}) - \vec{A} \cdot (\nabla \times \vec{B})\) and the integral form of Ampère's law for steady currents.
Why this matters
Magnetic materials are ubiquitous, yet their internal currents are too small to measure directly; the \(\vec{H}\) field provides the macroscopic tool to handle them.
So far we have treated magnetic fields as arising solely from free currents, such as those in copper wires. However, most magnetic phenomena in nature—permanent magnets, electromagnets with iron cores, and magnetic storage media—involve the alignment of atomic magnetic dipoles. These microscopic currents are dense and complex. To analyze them without summing over every electron orbit, we introduce the magnetization vector \(\vec{M}\). This lecture bridges the gap between the microscopic Lorentz force and the macroscopic engineering quantities, defining the auxiliary field \(\vec{H}\) which allows us to ignore the complex bound currents and focus only on the controllable free currents.
The Idea: Magnetization as a Current Density
Imagine a block of material where every atom acts like a tiny bar magnet. If these dipoles are randomly oriented, their effects cancel. If they align, the material becomes magnetized. We define the magnetization \(\vec{M}\) as the net magnetic dipole moment per unit volume. While we cannot see these individual atomic currents, their collective effect is mathematically identical to a continuous flow of charge. This "bound" current is not a flow of charge carriers moving through the material like in a wire, but rather the result of circulating charges within atoms. By treating magnetization as a source of current, we can apply the standard tools of magnetostatics, such as Ampère's law, to matter itself.
Bound Volume and Surface Currents
Consider a volume of magnetized material. The derivation D-056 shows that the vector potential generated by a distribution of dipoles is identical to that generated by a specific current distribution. This current splits into two parts: a volume current and a surface current. The volume current density is given by the curl of the magnetization:
This term is non-zero only where the magnetization changes direction or magnitude within the material. For a uniformly magnetized object, \(\nabla \times \vec{M} = 0\), meaning there is no volume current. However, at the boundary of the material, the magnetization drops abruptly to zero. This discontinuity creates a surface current density:
Here, \(\hat{n}\) is the outward normal to the surface. This surface current is the dominant source of the external magnetic field for uniformly magnetized bodies. It is crucial to note that \(\vec{J}_b\) and \(\vec{K}_b\) are not independent sources; they are entirely determined by \(\vec{M}\). They are "bound" because they cannot be separated from the material itself.
Generalizing Ampère's Law
In vacuum, Ampère's law states that the curl of \(\vec{B}\) is proportional to the current density. In matter, the total current density is the sum of free currents \(\vec{J}_f\) (conduction currents we control) and bound currents \(\vec{J}_b\). Thus, the fundamental equation becomes:
Substituting \(\vec{J}_b = \nabla \times \vec{M}\), we get:
Rearranging terms to group the curls together:
This structure suggests defining a new field quantity, the magnetic field strength \(\vec{H}\), such that:
The beauty of this definition is that the curl of \(\vec{H}\) depends only on the free current:
Integrating over a surface \(S\) bounded by a loop \(C\), we obtain the macroscopic Ampère's law:
This is the primary reason \(\vec{H}\) is useful in engineering and macroscopic physics: it allows us to calculate fields in complex materials by considering only the currents we explicitly drive, ignoring the intricate atomic details.
Boundary Conditions for H
Just as \(\vec{B}\) has boundary conditions derived from Gauss's and Ampère's laws, \(\vec{H}\) has its own conditions. Applying the integral form of \(\nabla \times \vec{H} = \vec{J}_f\) to a rectangular loop straddling the interface between two media (with negligible free surface current), we find that the tangential component of \(\vec{H}\) is continuous:
where \(\vec{K}_f\) is the free surface current density. If there is no free current on the surface, \(\vec{H}_{1t} = \vec{H}_{2t}\). This contrasts with \(\vec{B}\), whose tangential component is discontinuous by \(\mu_0 \vec{K}_{\text{total}}\). The normal component of \(\vec{B}\) is always continuous (\(\nabla \cdot \vec{B} = 0\)), but the normal component of \(\vec{H}\) is discontinuous if the magnetization changes across the boundary.
The derivation
Magnetized Matter, Bound Currents and H
A body carrying magnetization \(\vec{M}(\vec{r})\) (magnetic dipole moment per unit volume) produces exactly the same vector potential, and hence the same \(\vec{B}\), as an ordinary bound volume current \(\vec{J}_b=\nabla\times\vec{M}\) together with a bound surface current \(\vec{K}_b=\vec{M}\times\hat{n}\). Consequently Ampère's law reads \(\nabla\times\vec{B}=\mu_0(\vec{J}_f+\vec{J}_b)\), and the auxiliary field \(\vec{H}\equiv\dfrac{\vec{B}}{\mu_0}-\vec{M}\) obeys \(\nabla\times\vec{H}=\vec{J}_f\), i.e. \(\oint\vec{H}\cdot d\vec{l}=I_{f,\text{enc}}\), with only the free current on the right.
A common misconception is that \(\vec{H}\) is the "true" magnetic field and \(\vec{B}\) an auxiliary quantity. It is \(\vec{B}\) that exerts forces on moving charges, \(\vec{F} = q\vec{v} \times \vec{B}\); \(\vec{H}\) does not appear in the Lorentz force law. In vacuum \(\vec{H}\) is simply \(\vec{B}/\mu_0\); inside matter it is a bookkeeping field whose curl is set by the free current alone. Note that \(\nabla\cdot\vec{H} = -\nabla\cdot\vec{M}\) need not vanish, so \(\vec{H}\) is not fixed by the free current alone (a bar magnet has \(\vec{H} \ne 0\) with no free current at all). C
Worked example
Problem. A long solenoid of radius \(R = 5.0\ \mathrm{cm}\) has \(n = 1000\ \mathrm{turns/m}\) and carries a free current \(I = 2.0\ \mathrm{A}\). The solenoid is filled with a linear magnetic material with relative permeability \(\mu_r = 500\). Calculate the magnetic field strength \(\vec{H}\), the magnetic flux density \(\vec{B}\), and the bound surface current density \(\vec{K}_b\) at the surface of the core.
- Determine \(\vec{H}\) using Ampère's law for free currents. For a long solenoid, the field inside is uniform and outside is zero. The enclosed free current per unit length is \(nI\). Thus, \(H = nI\).
- Calculate \(H\): \(H = 1000\ \mathrm{m^{-1}} \times 2.0\ \mathrm{A} = 2000\ \mathrm{A/m}\). The direction is along the axis.
- Determine \(\vec{B}\) using the constitutive relation \(\vec{B} = \mu \vec{H} = \mu_0 \mu_r \vec{H}\). Use \(\mu_0 = 4\pi \times 10^{-7}\ \mathrm{T\cdot m/A}\).
- Calculate \(B\): \(B = (4\pi \times 10^{-7}) \times 500 \times 2000\). Note that \(500 \times 2000 = 10^6\). So \(B = 4\pi \times 10^{-7} \times 10^6 = 4\pi \times 10^{-1} = 0.4\pi\ \mathrm{T}\).
- Determine \(\vec{M}\) from \(\vec{M} = \frac{\vec{B}}{\mu_0} - \vec{H}\). Alternatively, for linear media, \(\vec{M} = \chi_m \vec{H}\) where \(\chi_m = \mu_r - 1 = 499\). So \(M = 499 \times 2000 = 998000\ \mathrm{A/m}\).
- Calculate the bound surface current density \(\vec{K}_b = \vec{M} \times \hat{n}\). At the cylindrical surface, \(\hat{n}\) is radial. \(\vec{M}\) is axial. The cross product gives a direction azimuthal. Magnitude \(K_b = M = 998000\ \mathrm{A/m}\).
Units check. \(H\) is in \(\mathrm{A/m}\). \(B\) is in \(\mathrm{T}\) (\(\mathrm{N/(A\cdot m)}\)). \(K_b\) is surface current, so \(\mathrm{A/m}\). The values are consistent with high-permeability materials where \(B\) is large but \(H\) is determined solely by the free current.
Three quick tests
- What is the relationship between \(\vec{H}\) and \(\vec{B}\) in a vacuum?
Answer
In vacuum, \(\vec{M} = 0\), so \(\vec{H} = \vec{B}/\mu_0\). They are proportional and point in the same direction. - If a material has uniform magnetization \(\vec{M}\), where is the bound current located?
Answer
Since \(\nabla \times \vec{M} = 0\) for uniform \(\vec{M}\), the volume current \(\vec{J}_b\) is zero. The bound current exists only on the surface as \(\vec{K}_b = \vec{M} \times \hat{n}\). - Why is \(\oint \vec{H} \cdot d\vec{l} = I_{f,\text{enc}}\) preferred over \(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{\text{total}}\) for calculating fields in magnetic cores?
Answer
Because \(I_{f,\text{enc}}\) is known (the current in the wire), whereas \(I_{\text{total}}\) includes unknown bound currents that depend on the material's response. \(\vec{H}\) isolates the source we control.
Problem set for PU-102 →
Each derivation in this unit ends with five graded problems with full solutions.
Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.