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PU-202 / L16 · lecture

Scattering, Reflection, and Transmission at a Step

~6 min read · Tier toggle changes depth (T1 plain · T2 standard · T3 rigour)

BEFORE YOU START

You should be comfortable solving the time-independent Schrödinger equation in regions of constant potential and applying the continuity conditions for the wavefunction and its first derivative at potential boundaries.

Why this matters

Scattering at a potential step is the simplest non-trivial problem that reveals the probabilistic nature of quantum mechanics.

In classical mechanics, a particle with energy \( E \) encountering a step of height \( V_0 \) either passes through if \( E > V_0 \) or reflects completely if \( E < V_0 \). Quantum mechanics introduces a more subtle reality: even when \( E > V_0 \), there is a non-zero probability of reflection, and when \( E < V_0 \), the wavefunction penetrates into the classically forbidden region. This lecture establishes the formalism for calculating reflection and transmission coefficients, which are fundamental to understanding electron transport in semiconductors and nuclear reactions.

The Physical Picture

Imagine a stream of particles moving from left to right towards a sudden change in potential energy. In the region where the potential is constant, the wavefunction behaves like a plane wave, representing a particle with a definite momentum. When the particle reaches the boundary where the potential changes, the wave does not simply stop or bounce back like a billiard ball. Instead, part of the wave is reflected back towards the source, and part is transmitted into the new region. The relative amplitudes of these reflected and transmitted waves are determined by the requirement that the total probability density and its flow must remain continuous across the boundary. This continuity is the quantum mechanical analogue of energy and momentum conservation, but it applies to the wave nature of the particle rather than its particle nature.

Wavefunctions in Each Region

Consider a potential step defined by \( V(x) = 0 \) for \( x < 0 \) and \( V(x) = V_0 \) for \( x > 0 \). We assume an incident wave of energy \( E \) coming from the left. In region I (\( x < 0 \)), the time-independent Schrödinger equation yields a solution consisting of an incident wave and a reflected wave. In region II (\( x > 0 \)), the solution is a transmitted wave. The general forms are:

\[ \psi_{\mathrm{I}}(x) = A e^{ik_1 x} + B e^{-ik_1 x}, \quad x < 0 \]
\[ \psi_{\mathrm{II}}(x) = C e^{ik_2 x}, \quad x > 0 \]

Here, \( k_1 = \sqrt{2mE}/\hbar \) and \( k_2 = \sqrt{2m(E - V_0)}/\hbar \). Note that if \( E < V_0 \), \( k_2 \) becomes imaginary, indicating exponential decay rather than oscillation. The coefficients \( A \), \( B \), and \( C \) are determined by the boundary conditions at \( x = 0 \).

Applying Boundary Conditions

According to the continuity conditions derived in D-145, both the wavefunction and its first derivative must be continuous at \( x = 0 \). Applying \( \psi_{\mathrm{I}}(0) = \psi_{\mathrm{II}}(0) \) gives:

\[ A + B = C \]

Applying \( \psi'_{\mathrm{I}}(0) = \psi'_{\mathrm{II}}(0) \) gives:

\[ ik_1(A - B) = ik_2 C \]

Solving this system of two linear equations for \( B \) and \( C \) in terms of \( A \) yields the reflection and transmission amplitudes. The ratio \( B/A \) represents the amplitude of the reflected wave relative to the incident wave, while \( C/A \) represents the transmission amplitude. These ratios depend only on the ratio of the wave numbers \( k_1 \) and \( k_2 \), which in turn depend on the energy \( E \) and the step height \( V_0 \).

Reflection and Transmission Coefficients

The physical interpretation of the coefficients requires the concept of probability current, defined in D-007 as \( j = \frac{\hbar}{m} \mathrm{Im}(\psi^* \frac{\partial \psi}{\partial x}) \). For a plane wave \( \psi = A e^{ikx} \), the current is \( j = \frac{\hbar k}{m} |A|^2 \). The reflection coefficient \( R \) is the ratio of the reflected current to the incident current, and the transmission coefficient \( T \) is the ratio of the transmitted current to the incident current.

\[ R = \left| \frac{B}{A} \right|^2, \quad T = \frac{k_2}{k_1} \left| \frac{C}{A} \right|^2 \]

Substituting the solutions for \( B \) and \( C \) from the boundary conditions, we find:

\[ R = \left( \frac{k_1 - k_2}{k_1 + k_2} \right)^2, \quad T = \frac{4 k_1 k_2}{(k_1 + k_2)^2} \]

A crucial result is that \( R + T = 1 \). This expresses the conservation of probability: the total probability flux entering the step must equal the total probability flux leaving it, either by reflection or transmission. This is a direct consequence of the continuity equation \( \partial \rho / \partial t + \partial j / \partial x = 0 \).

The derivations

◆ DERIVATION EMBED · D-145 · not re-derived here

Continuity Conditions at Potential Steps

Across any point x = a where the potential V(x) has a finite jump discontinuity, a solution of the one-dimensional time-independent Schrödinger equation and its first derivative are both continuous: ψ(a+) = ψ(a−) and ψ′(a+) = ψ′(a−). These are not extra postulates but consequences of the equation itself, valid whenever V stays bounded.

ψ(a+) = ψ(a−)   and   ψ′(a+) = ψ′(a−)   (finite V)
Open full derivation →
◆ DERIVATION EMBED · D-007 · not re-derived here

Probability Current and the Continuity Equation

Derives the probability current density and the local continuity equation guaranteeing conservation of probability under Schrödinger evolution.

∂ρ/∂t + ∂j/∂x = 0,    j = (ħ/m) Im( ψ* ∂ψ/∂x )
Open full derivation →
Tier 3 · watch out

When \( E < V_0 \), \( k_2 = i\kappa \) is imaginary and the wave in region II is evanescent, \( C e^{-\kappa x} \). It is real up to a constant phase, so it carries no probability current: \( T = 0 \) and \( |B/A| = 1 \), so \( R = 1 \) exactly. The particle penetrates a distance of order \( 1/\kappa \) into the step but is always reflected; the reflected wave is only shifted in phase. Do not substitute an imaginary \( k_2 \) into \( T = 4k_1k_2/(k_1 + k_2)^2 \): that formula assumes a travelling transmitted wave. C

Worked example

Problem. An electron with energy \( E = 5.0 \ \mathrm{eV} \) is incident from the left on a potential step of height \( V_0 = 3.0 \ \mathrm{eV} \). Calculate the reflection coefficient \( R \) and the transmission coefficient \( T \).

  1. Determine the wave numbers \( k_1 \) and \( k_2 \). Since \( k \propto \sqrt{E} \), the ratio \( k_2/k_1 = \sqrt{(E - V_0)/E} \).
  2. Calculate the ratio: \( \frac{k_2}{k_1} = \sqrt{\frac{5.0 - 3.0}{5.0}} = \sqrt{\frac{2.0}{5.0}} = \sqrt{0.4} \approx 0.6325 \).
  3. Use the formula for \( R \): \( R = \left( \frac{1 - k_2/k_1}{1 + k_2/k_1} \right)^2 \).
  4. Substitute the value: \( R = \left( \frac{1 - 0.6325}{1 + 0.6325} \right)^2 = \left( \frac{0.3675}{1.6325} \right)^2 \approx (0.2251)^2 \approx 0.0507 \).
  5. Calculate \( T \) using \( T = 1 - R \) or the direct formula: \( T = 1 - 0.0507 = 0.9493 \).
\[ R \approx 0.051, \quad T \approx 0.949 \]

Units check. The coefficients \( R \) and \( T \) are dimensionless ratios of currents, so they are unitless. The energy values are in eV, but since they appear only in ratios, the units cancel out correctly.

CHECK YOURSELF

Three quick tests

  1. What happens to the reflection coefficient \( R \) as the step height \( V_0 \) approaches zero?
    AnswerAs \( V_0 \to 0 \), \( k_2 \to k_1 \), so \( R \to 0 \) and \( T \to 1 \). The particle passes through without reflection.
  2. Why is \( T \) not simply \( |C/A|^2 \)?
    AnswerBecause the probability current depends on the wave number \( k \). The transmitted current is proportional to \( k_2 |C|^2 \), while the incident current is proportional to \( k_1 |A|^2 \). Thus, \( T = \frac{k_2}{k_1} |C/A|^2 \).
  3. If \( E < V_0 \), is the transmission coefficient \( T \) zero?
    AnswerYes. The evanescent wave in region II carries no current, so \( T = 0 \) and \( R = 1 \). The wavefunction is still non-zero for a short distance (of order \( 1/\kappa \)) inside the step.
PROBLEMS

Problem set for PU-202 →

Each derivation in this unit ends with five graded problems with full solutions.

NOTES

Lecture notes drafted with a local model and checked line by line by the editor; every number in the worked example was recomputed.

Derivations cited: D-145 · D-007 · Threads: matter, waves, energy