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PU-203 / L21 · lecture

Equivalence of Ensembles and the Thermodynamic Limit

~5 min read · Tier toggle changes depth (T1 plain · T2 standard · T3 rigour)

BEFORE YOU START

You should be comfortable with the definitions of the microcanonical and canonical ensembles, the concept of entropy as a function of energy, and the basic properties of the Laplace transform.

Why this matters

This lecture resolves the apparent tension between different statistical mechanical frameworks.

In statistical physics, we often choose between the microcanonical ensemble (isolated system) and the canonical ensemble (system in contact with a heat bath) based on convenience. However, for macroscopic systems, these descriptions must yield identical thermodynamic predictions. Understanding why this equivalence holds, and under what conditions it breaks down, is crucial for interpreting experimental data and for understanding the limits of classical statistical mechanics. It bridges the gap between microscopic counting of states and macroscopic thermodynamic potentials.

The Core Idea in Plain Language

Imagine a large box of gas. If you isolate it, its energy is fixed, but the individual molecules exchange energy constantly. If you put it in contact with a huge heat bath, the box's energy can fluctuate slightly as it exchanges heat with the bath. For a tiny system, these two situations would look very different. However, for a macroscopic system with a huge number of particles, the energy fluctuations in the canonical case are incredibly small compared to the total energy. The system spends almost all its time at a single, specific energy value. This means that whether you calculate properties assuming fixed energy or fixed temperature, you get the same answer. The "sharpness" of the energy distribution is the key to this equivalence.

The Laplace Transform Connection

The mathematical link between the two ensembles is the Laplace transform. The canonical partition function \( Z(\beta) \) is related to the microcanonical density of states \( \Omega(E) \) by the integral:

\[ Z(\beta) = \int dE \, \Omega(E) e^{-\beta E} \]

Here, \( \beta = 1/k_B T \). The density of states \( \Omega(E) \) grows exponentially with energy, while the Boltzmann factor \( e^{-\beta E} \) decays exponentially. The product of these two terms creates a sharp peak. This peak occurs at the energy \( E^* \) where the microcanonical temperature of the system matches the temperature of the bath. This is the point of maximum contribution to the integral.

Steepest Descent and the Gaussian Peak

To evaluate the integral for large systems, we use the method of steepest descent. We expand the logarithm of the integrand around the peak \( E^* \). Let \( f(E) = \ln \Omega(E) - \beta E \). The first derivative vanishes at \( E^* \), and the second derivative determines the width of the peak. For a system with extensive entropy and positive heat capacity \( C \), the second derivative is negative, ensuring a maximum. Since \( \partial^2 \ln\Omega/\partial E^2 = -1/(k_B T^2 C) \), the integral is then approximated by a Gaussian centred at \( E^* \) with variance \( k_B T^2 C \).

\[ Z(\beta) \approx \Omega(E^*) e^{-\beta E^*} \sqrt{2\pi k_B T^2 C} \]

The width of this Gaussian, \( \sigma_E \), is proportional to \( \sqrt{k_B T^2 C} \). Since the heat capacity \( C \) is extensive (proportional to \( N \)), the relative width \( \sigma_E / E^* \) scales as \( 1/\sqrt{N} \). As \( N \to \infty \), this relative width vanishes, meaning the energy distribution becomes a delta function. This is the mathematical statement of ensemble equivalence.

Free Energy and the Legendre Transform

From the steepest descent approximation, we can extract the canonical free energy \( F(T) \). Taking the logarithm of \( Z(\beta) \) and using \( F = -k_B T \ln Z \), we find:

\[ F(T) = E^*(T) - T S(E^*(T)) + \mathcal{O}(k_B T \ln N) \]

The dominant term \( E^* - T S(E^*) \) is precisely the Legendre transform of the microcanonical entropy \( S(E) \) with respect to energy. This shows that the canonical free energy is not an independent quantity but is derived directly from the microcanonical entropy. The correction term \( \mathcal{O}(k_B T \ln N) \) represents the finite-size effects due to the finite width of the energy distribution. These corrections vanish in the thermodynamic limit \( N \to \infty \), confirming the equivalence of the ensembles.

The derivation

◆ DERIVATION EMBED · D-158 · not re-derived here

Equivalence of Ensembles in the Thermodynamic Limit

The canonical partition function is the Laplace transform of the microcanonical density of states, Z(β) = ∫ dE Ω(E) e−βE. Evaluating this integral by steepest descent shows that, for any system whose entropy is extensive and concave (heat capacity C > 0), the integrand is a sharp Gaussian of relative width ∼ 1/√N centred on the energy E* where the microcanonical temperature equals the bath temperature. Consequently the canonical free energy equals the Legendre transform of the microcanonical entropy, F(T) = E* − T S(E*), up to corrections of relative order (ln N)/N → 0.

F(T) = E*(T) − T S(E*(T)) + 𝒪(kT ln N),    σE/E* = 𝒪(N−1/2)
Open full derivation →
Tier 3 · watch out

Ensemble equivalence relies on the concavity of the entropy function \( S(E) \). If the entropy is non-concave (e.g., in systems with long-range interactions like gravity or certain magnetic systems), the energy distribution in the canonical ensemble can become bimodal or broad, leading to ensemble inequivalence. In such cases, the microcanonical and canonical ensembles predict different phase transitions, and the thermodynamic limit does not restore equivalence. C

Worked example

Problem. Consider a system of \( N = 10^{23} \) particles with a heat capacity \( C = 3 N k_B \). Calculate the relative energy fluctuation \( \sigma_E / E \) in the canonical ensemble at temperature \( T = 300 \ \mathrm{K} \). Assume the total energy is \( E = 3 N k_B T \).

  1. Identify the formula for the relative energy fluctuation: \( \frac{\sigma_E}{E} = \sqrt{\frac{k_B T^2 C}{E^2}} \).
  2. Substitute the given values: \( C = 3 N k_B \) and \( E = 3 N k_B T \).
  3. Simplify the expression: \( \frac{\sigma_E}{E} = \sqrt{\frac{k_B T^2 (3 N k_B)}{(3 N k_B T)^2}} = \sqrt{\frac{3 N k_B^2 T^2}{9 N^2 k_B^2 T^2}} = \sqrt{\frac{1}{3N}} \).
  4. Calculate the numerical value: \( \sqrt{\frac{1}{3 \times 10^{23}}} \approx \sqrt{3.33 \times 10^{-24}} \approx 1.8 \times 10^{-12} \).
\[ \frac{\sigma_E}{E} \approx 1.8 \times 10^{-12} \]

Units check. The ratio \( \sigma_E / E \) is dimensionless, as expected. The small value confirms that energy fluctuations are negligible for macroscopic systems, supporting the equivalence of ensembles.

CHECK YOURSELF

Three quick tests

  1. What is the mathematical relationship between the canonical partition function and the microcanonical density of states?
    AnswerThe canonical partition function is the Laplace transform of the microcanonical density of states.
  2. How does the relative energy fluctuation scale with the number of particles \( N \)?
    AnswerIt scales as \( 1/\sqrt{N} \), vanishing in the thermodynamic limit.
  3. Under what conditions can ensemble equivalence fail?
    AnswerWhen the entropy is non-concave, such as in systems with long-range interactions.
PROBLEMS

Problem set for PU-203 →

Each derivation in this unit ends with five graded problems with full solutions.

NOTES

Lecture notes checked line by line by the editor; every number in the worked example was recomputed.

Derivations cited: D-158 · Threads: energy, matter, chance