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Depth
PU-204 / L15 · lecture

Waves in Conductors and Skin Depth

~7 min read · Tier toggle changes depth (T1 plain · T2 standard · T3 rigour)

BEFORE YOU START

You should be comfortable with Maxwell’s equations in matter, the definition of complex permittivity, and the basics of phasor notation for harmonic fields.

Why this matters

Understanding how electromagnetic waves penetrate conductors is essential for designing antennas, shielding, and high-frequency circuits.

In the previous lecture, we considered waves in lossless dielectrics where the wavevector is real. Here, we introduce conductivity, which makes the wavevector complex. This leads to a fundamental change in wave behaviour: the fields are no longer purely oscillatory but decay exponentially as they propagate. This phenomenon, quantified by the skin depth, explains why high-frequency currents are confined to the surface of conductors and why perfect shielding is impossible at finite frequencies.

The Physical Picture

Imagine sending a radio wave into a metal block. In a perfect insulator, the wave would travel through indefinitely, losing no energy. In a conductor, however, the electric field drives free electrons into motion, creating a current. This current dissipates energy as heat via Joule heating. Consequently, the wave loses amplitude as it penetrates the material. The distance over which the field amplitude drops by a factor of \( 1/e \) is called the skin depth. For good conductors like copper, this depth is very small at radio frequencies, meaning the wave is effectively absorbed in a thin layer near the surface. Furthermore, the magnetic field does not stay in phase with the electric field; it lags by a specific angle, a direct consequence of the energy dissipation mechanism.

Complex Wavevector and Propagation

Starting from Maxwell’s equations in a linear, homogeneous medium with conductivity \( \sigma \), we substitute the free current density \( \vec{J}_f = \sigma \vec{E} \) into Ampère’s law. For a monochromatic plane wave, this leads to a dispersion relation where the square of the complex wavevector \( \tilde{k} \) is given by:

\[ \tilde{k}^2 = \mu\varepsilon\omega^2 + i\,\mu\sigma\omega \]

Here, \( \mu \) is the permeability, \( \varepsilon \) is the permittivity, and \( \omega \) is the angular frequency. The imaginary term \( i\,\mu\sigma\omega \) arises from the conduction current. We define the complex wavevector as \( \tilde{k} = k + i\kappa \), where \( k \) is the real part governing the phase oscillation and \( \kappa \) is the imaginary part governing the exponential decay. The electric field can be written in phasor form as \( \vec{E} = \vec{E}_0 e^{i(kz - \omega t)} e^{-\kappa z} \). The term \( e^{-\kappa z} \) represents the attenuation of the wave amplitude as it travels in the \( z \)-direction.

The Good Conductor Approximation

For most metals at optical and radio frequencies, the conduction current dominates over the displacement current. This condition is expressed as \( \sigma \gg \varepsilon\omega \). Under this assumption, the term \( \mu\varepsilon\omega^2 \) in the dispersion relation becomes negligible compared to \( i\,\mu\sigma\omega \). The equation simplifies to \( \tilde{k}^2 \approx i\,\mu\sigma\omega \). To solve for \( \tilde{k} \), we take the square root of \( i \). Since \( i = e^{i\pi/2} \), the square root is \( e^{i\pi/4} = \frac{1}{\sqrt{2}}(1 + i) \). Thus, \( \tilde{k} \approx \sqrt{\frac{\mu\sigma\omega}{2}} (1 + i) \). This implies that the real and imaginary parts are equal: \( k = \kappa \). We define the skin depth \( \delta \) as the inverse of this common value:

\[ \delta = \frac{1}{k} = \frac{1}{\kappa} = \sqrt{\frac{2}{\mu\sigma\omega}} \]

The electric field then takes the form \( \vec{E} = E_0 e^{-z/\delta} \cos\left(\frac{z}{\delta} - \omega t\right)\hat{\mathbf{x}} \). The field oscillates with a wavelength \( \lambda = 2\pi\delta \) and decays with a characteristic length \( \delta \). Note that \( \delta \) depends on the square root of the frequency; doubling the frequency reduces the skin depth by a factor of \( \sqrt{2} \).

Field Phase and Magnitude

In a lossless dielectric, the electric and magnetic fields are in phase, and their magnitudes are related by the intrinsic impedance of the medium. In a good conductor, the situation is different. Using Faraday’s law \( \nabla \times \vec{E} = -\frac{\partial \vec{B}}{\partial t} \), we can determine the magnetic field. For a wave propagating in the \( z \)-direction with \( \vec{E} \) in the \( x \)-direction, the magnetic field \( \vec{B} \) is in the \( y \)-direction. The complex amplitude ratio is derived from the wavevector. In the good conductor limit, the magnitude ratio is:

\[ \frac{|B_0|}{|E_0|} = \sqrt{\frac{\mu\sigma}{\omega}} \]

More importantly, the phase relationship changes. The complex wavevector \( \tilde{k} \) has an argument of \( \pi/4 \). This results in the magnetic field lagging the electric field by \( \pi/4 \) radians (45 degrees). This phase shift is a direct signature of the dissipative nature of the medium. The energy flow, described by the Poynting vector, is no longer purely real; it has an imaginary component representing reactive power, but the real part indicates the net energy dissipated in the conductor.

The derivation

◆ DERIVATION EMBED · D-173 · not re-derived here

Waves in Conductors and Skin Depth

For a monochromatic plane wave of angular frequency \( \omega \) propagating in a linear, homogeneous, ohmic medium (permittivity \( \varepsilon \), permeability \( \mu \), conductivity \( \sigma \), with \( \vec{J}_f = \sigma \vec{E} \)), Maxwell's equations require the wavevector to be complex, \( \tilde{k} = k + i\kappa \), with \( \tilde{k}^2 = \mu\varepsilon\omega^2 + i\,\mu\sigma\omega \). The fields decay as \( e^{-\kappa z} \) while oscillating as \( e^{i(kz-\omega t)} \). In the good-conductor regime \( \sigma \gg \varepsilon\omega \) this reduces to \( k = \kappa = 1/\delta \) with the skin depth \( \delta = \sqrt{2/(\mu\sigma\omega)} \), and the magnetic field lags the electric field by \( \pi/4 \) with magnitude ratio \( |B_0|/|E_0| = \sqrt{\mu\sigma/\omega} \).

\[ \tilde{k}^2 = \mu\varepsilon\omega^2 + i\,\mu\sigma\omega, \qquad \vec{E} = E_0\, e^{-z/\delta} \cos\!\left(\frac{z}{\delta} - \omega t\right)\hat{\mathbf{x}}, \qquad \delta = \sqrt{\frac{2}{\mu\sigma\omega}} \;\;(\sigma \gg \varepsilon\omega) \]
Open full derivation →
Tier 3 · watch out

A common misconception is that the skin depth is a fixed material property. In reality, \( \delta \) depends on frequency. At very low frequencies (DC limit), the concept of skin depth breaks down because the wave does not propagate; instead, we have static fields that penetrate the entire conductor. The formula \( \delta = \sqrt{2/(\mu\sigma\omega)} \) is only valid in the good conductor regime where \( \omega \) is sufficiently high such that \( \sigma \gg \varepsilon\omega \). For poor conductors or very low frequencies, the full complex expression for \( \tilde{k} \) must be used, and the phase lag is not exactly \( \pi/4 \). C

Worked example

Problem. A plane electromagnetic wave with frequency \( f = 1.0 \times 10^9 \ \mathrm{Hz} \) is incident on a copper block. The conductivity of copper is \( \sigma = 5.8 \times 10^7 \ \mathrm{S/m} \), and the permeability is approximately the vacuum value \( \mu = 4\pi \times 10^{-7} \ \mathrm{H/m} \). Calculate the skin depth \( \delta \) and the ratio of the magnetic field amplitude to the electric field amplitude \( |B_0|/|E_0| \).

  1. Calculate the angular frequency \( \omega = 2\pi f = 2\pi (1.0 \times 10^9) \approx 6.28 \times 10^9 \ \mathrm{rad/s} \).
  2. Compute the product \( \mu\sigma\omega \): \( (4\pi \times 10^{-7})(5.8 \times 10^7)(6.28 \times 10^9) \approx 4.58 \times 10^{11} \ \mathrm{s^{-2}} \).
  3. Calculate the skin depth \( \delta = \sqrt{2 / (4.58 \times 10^{11})} \approx \sqrt{4.37 \times 10^{-12}} \approx 2.09 \times 10^{-6} \ \mathrm{m} \).
  4. Calculate the field ratio \( |B_0|/|E_0| = \sqrt{\mu\sigma/\omega} = \sqrt{(4\pi \times 10^{-7})(5.8 \times 10^7) / (6.28 \times 10^9)} = \sqrt{72.9 / (6.28 \times 10^{9})} \approx \sqrt{1.16 \times 10^{-8}} \approx 1.08 \times 10^{-4} \ \mathrm{s/m} \).
\[ \delta \approx 2.1 \ \mu\mathrm{m}, \qquad \frac{|B_0|}{|E_0|} \approx 1.1 \times 10^{-4} \ \mathrm{s/m} \]

Units check. The skin depth is in metres, as expected. The ratio \( B/E \) has units of \( \mathrm{T}/(\mathrm{V/m}) = \mathrm{T \cdot m/V} \). Since \( \mathrm{V} = \mathrm{Wb/s} \) and \( \mathrm{T} = \mathrm{Wb/m^2} \), the units become \( (\mathrm{Wb/m^2}) \cdot \mathrm{m} / (\mathrm{Wb/s}) = \mathrm{s/m} \). This is consistent with the derived formula.

Compare vacuum, where \(B_0/E_0 = 1/c = 3.3 \times 10^{-9}\ \mathrm{s\,m^{-1}}\): inside the copper the ratio is about \(3 \times 10^{4}\) times larger, so the wave in a good conductor is overwhelmingly magnetic.

CHECK YOURSELF

Three quick tests

  1. How does the skin depth change if the frequency is increased by a factor of 4?
    AnswerIt decreases by a factor of 2, since \( \delta \propto 1/\sqrt{f} \).
  2. What is the phase difference between the electric and magnetic fields in a good conductor?
    AnswerThe magnetic field lags the electric field by \( \pi/4 \) radians (45 degrees).
  3. Why is the displacement current negligible in the good conductor approximation?
    AnswerBecause the conduction current density \( \sigma E \) is much larger than the displacement current density \( \varepsilon \omega E \), i.e., \( \sigma \gg \varepsilon\omega \).
PROBLEMS

Problem set for PU-204 →

Each derivation in this unit ends with five graded problems with full solutions.

NOTES

Lecture notes checked line by line by the editor; every number in the worked example was recomputed.

Derivations cited: D-173 · Threads: force, energy, light