BCS Gap Equation and the Superconducting Gap
Statement
Starting from the reduced BCS pairing Hamiltonian with an attractive interaction \(-V\) between time-reversed electron pairs \((\mathbf{k}\uparrow,-\mathbf{k}\downarrow)\), a mean-field decoupling and a Bogoliubov canonical transformation diagonalise the Hamiltonian in terms of quasiparticles of energy \(E_{\mathbf{k}}=\sqrt{\xi_{\mathbf{k}}^{2}+\Delta^{2}}\), yielding the self-consistent gap equation \(1=V N(0)\int_{0}^{\hbar\omega_D}\frac{\tanh(\beta E/2)}{2E}\,d\xi\), whose \(T=0\) solution is \(\Delta_0=2\hbar\omega_D e^{-1/N(0)V}\) and whose vanishing-gap limit fixes the critical temperature \(k_B T_c=1.13\,\hbar\omega_D e^{-1/N(0)V}\).
Why it matters
The gap equation is the quantitative heart of superconductivity. It converts the qualitative Cooper-pair instability into a full thermodynamic order parameter \(\Delta(T)\), predicts the energy gap seen in tunnelling and infrared absorption, and yields the celebrated universal ratio \(2\Delta_0/k_BT_c\approx 3.53\) that holds across weak-coupling superconductors independent of material detail.
It is also the prototype of every mean-field theory of a fermionic condensate: the same Bogoliubov-de Gennes structure reappears in superfluid \(^3\)He, neutron-star pairing, colour superconductivity in dense quark matter, and the BCS side of the BCS-BEC crossover in ultracold atoms. Mastering this derivation is mastering the template for spontaneously broken \(U(1)\) symmetry in a fermion system.
Assumptions
Derivation
Reading. The gap \(\Delta(T)\) is fixed self-consistently: an electron pair feels an attraction \(V\) but only pairs where a coherent gap \(\Delta\) already exists, weighted by how many quasiparticle states are thermally excited via \(\tanh\). At \(T=0\) the \(\tanh\to1\) and the integral gives \(\Delta_0=2\hbar\omega_D\,e^{-1/N(0)V}\); as \(T\to T_c\) the gap vanishes and \(k_BT_c=1.13\,\hbar\omega_D\,e^{-1/N(0)V}\).
Units check. \(N(0)\) has units \([\text{energy}]^{-1}\) (states per unit energy per spin), \(V\) is \([\text{energy}]\), so \(N(0)V\) is dimensionless — correct for an exponent. The integrand \(d\xi/\sqrt{\xi^2+\Delta^2}\) is dimensionless (energy over energy), so the right side is dimensionless, matching the \(1\) on the left. \(\Delta_0\sim\hbar\omega_D\) carries energy units as required.
Limiting cases
- \(T\to0\): \(\tanh\to1\), giving \(\Delta_0=2\hbar\omega_D e^{-1/N(0)V}\) — the maximum gap.
- \(T\to T_c^-\): set \(\Delta=0\) in the integrand, yielding \(k_BT_c=(2e^{\gamma}/\pi)\hbar\omega_D e^{-1/N(0)V}\approx1.134\,\hbar\omega_D e^{-1/N(0)V}\) with \(\gamma\) the Euler-Mascheroni constant.
- Weak coupling \(N(0)V\ll1\): \(\Delta_0/E_F\ll1\); pairing is a thin Fermi-surface effect and the exponential makes \(T_c\) non-analytic in \(V\) (no perturbation theory reaches it).
- Universal ratio: dividing the two limits, \(2\Delta_0/k_BT_c=2\pi/e^{\gamma}\approx3.528\), independent of \(\omega_D\), \(N(0)\), and \(V\).
- Near \(T_c\): \(\Delta(T)\approx3.06\,k_BT_c\sqrt{1-T/T_c}\), the mean-field square-root onset of the order parameter.
Breaks when
- Strong coupling \(\lambda=N(0)V\gtrsim0.5\): retardation and the finite phonon lifetime matter; the instantaneous \(-V\) is replaced by the frequency-dependent Eliashberg kernel and \(2\Delta_0/k_BT_c\) rises above 3.53 (e.g. Pb, Hg).
- Low dimensions (1D/2D): the neglected phase fluctuations diverge; long-range order is destroyed by the Mermin-Wagner/BKT mechanism and the true transition is not the mean-field \(T_c\).
- Anisotropic / nodal pairing: for d-wave (cuprates) or p-wave (\(^3\)He) the scalar \(\Delta\) becomes \(\Delta_{\mathbf{k}}\) with sign changes and nodes; the flat-DOS s-wave gap equation gives the wrong \(T_c\) and thermodynamics.
- Magnetic impurities / pair breaking: spin-flip scattering breaks time-reversed pairs (Abrikosov-Gor'kov); gapless superconductivity appears and \(T_c\) is suppressed faster than the clean equation predicts.
Failure modes
- Cancelling \(\Delta\) from both sides of step 9 while forgetting that \(\Delta=0\) is always a (normal-state) solution — the non-trivial branch requires \(N(0)V>0\).
- Writing the quasiparticle energy as \(E_{\mathbf{k}}=\xi_{\mathbf{k}}+\Delta\) instead of \(\sqrt{\xi_{\mathbf{k}}^2+\Delta^2}\); the gap is the minimum of \(E\), not an additive shift.
- Integrating \(\xi\) from \(0\) to \(\infty\); the Debye cutoff \(\hbar\omega_D\) is essential — without it the log diverges and no gap scale emerges.
- Using \(\hbar\omega_D\) as the \(T=0\) prefactor for both \(\Delta_0\) and \(k_BT_c\) with the same numerical coefficient — the coefficients differ (\(2\) vs \(1.13\)), which is the whole content of the universal ratio.
- Confusing the single-particle gap \(\Delta\) with the condensation energy \(\tfrac12N(0)\Delta_0^2\); they scale differently in \(V\).
- Treating \(f(E_{\mathbf{k}})\) as the electron occupation rather than the quasiparticle occupation, giving the wrong sign in \(1-2f\).
Discussion
The physical content of the gap equation is spontaneous breaking of the global \(U(1)\) gauge symmetry associated with particle-number conservation. The mean field \(\Delta=|\Delta|e^{i\varphi}\) picks a phase \(\varphi\), and the ground state is a coherent superposition of states with different particle number — the BCS wavefunction \(\prod_{\mathbf{k}}(u_{\mathbf{k}}+v_{\mathbf{k}}c_{\mathbf{k}\uparrow}^{\dagger}c_{-\mathbf{k}\downarrow}^{\dagger})|0\rangle\). The rigidity of \(\varphi\) is precisely what carries dissipationless current, tying this derivation directly to the Meissner effect and flux quantisation.
The exponential \(e^{-1/N(0)V}\) is the derivation's most striking feature: it is non-analytic at \(V=0\), so no finite order of perturbation theory in the electron-phonon coupling ever produces superconductivity. This is why the phenomenon resisted explanation for nearly fifty years after its 1911 discovery — one must sum an infinite ladder of scattering (the Cooper channel) to see the instability that this mean field then stabilises. The prior Cooper-pair result supplies exactly that log-divergent pair susceptibility; the gap equation is its non-perturbative resummation.
The quasiparticles \(\gamma\) are coherent superpositions of an electron and a hole (\(u\) electron-like, \(v\) hole-like), so charge is not a good quantum number for excitations — only \(\pm1\) modulo the condensate. This particle-hole mixing is what tunnelling spectroscopy measures as the symmetric gap edges at \(\pm\Delta\), and it is the direct microscopic ancestor of Bogoliubov-de Gennes quasiparticles and, in the topological context, of Majorana zero modes where \(u=v\).
At the deepest level the gap function is an anomalous propagator \(F(\mathbf{k},\omega)=\langle T\,c_{\mathbf{k}\uparrow}c_{-\mathbf{k}\downarrow}\rangle\) that is nonzero only in the broken-symmetry phase; the mean-field gap equation is the leading (Hartree-Fock-Gor'kov) truncation of the Dyson equation for the \(2\times2\) Nambu Green's function. Promoting \(-V\) to the retarded phonon propagator \(D(\mathbf{k}-\mathbf{k}',\omega-\omega')\) and keeping the electron self-energy gives the Eliashberg equations, which reduce to BCS in the limit \(\omega_D\ll E_F\) with the coupling \(\lambda\) small — placing this entire result as one controlled limit of a fully retarded, strong-coupling field theory.
Common misconceptions. The gap is not a rigid band gap like a semiconductor's: it is a self-consistent, temperature-dependent order parameter that vanishes continuously at \(T_c\), and its very existence is the presence of the condensate, not a property of the bare band structure. Nor does \(\Delta\) equal the pairing binding energy of a single Cooper pair; \(\Delta\) is a collective mean field to which every pair on the Fermi surface contributes.
Worked examples
Reading. The measured \(T_c\) of Al is \(1.18\,\text{K}\); the weak-coupling estimate is the right order of magnitude, the overshoot reflecting the crudeness of \(N(0)V\) and Coulomb repulsion (the \(\mu^*\) correction) which the bare BCS formula omits.
Units check. \(k_B\Theta_D\) carries energy; the exponential is dimensionless; dividing through by \(k_B\) returns a temperature in kelvin.
Reading. A superconductor-insulator-superconductor tunnel junction of Nb shows a conductance gap edge at \(2\Delta_0\approx2.8\,\text{meV}\); the measured value is closer to \(3.0\,\text{meV}\) because Nb is a moderate-coupling material with \(2\Delta_0/k_BT_c\approx3.8\), slightly above the weak-coupling 3.53.
Units check. \(k_B\) in eV/K times \(T\) in K gives eV; scaling by \(10^3\) gives meV, the natural scale for superconducting gaps.
Problems
- Show that the constant term \(|\Delta|^2/V\) in \(\hat H_{MF}\) equals \(N(0)\Delta^2\times(1/N(0)V)\) and comment on why it is needed.
Solution
With \(\Delta=V\sum_{\mathbf{k}}\langle b_{\mathbf{k}}\rangle\), the mean-field factorisation \(b^{\dagger}b\to b^{\dagger}\langle b\rangle+\langle b^{\dagger}\rangle b-\langle b^{\dagger}\rangle\langle b\rangle\) leaves the subtraction \(-\sum\langle b^{\dagger}\rangle\langle b\rangle=-|\Delta|^2/V\) with sign flipped by the leading minus of the interaction, giving \(+|\Delta|^2/V\). Writing \(1/V=N(0)/(N(0)V)\) gives \(|\Delta|^2/V=N(0)\Delta^2/(N(0)V)\). It is needed to avoid double-counting the interaction energy already contained in the linear \(\Delta\) terms; without it the ground-state energy \(E_0\) and hence the condensation energy would be wrong. - Derive the condensation energy \(E_s-E_n=-\tfrac12N(0)\Delta_0^2\) at \(T=0\).
Solution
The ground-state energy is \(E_0=\sum_{\mathbf{k}}(\xi_{\mathbf{k}}-E_{\mathbf{k}})+\Delta^2/V\). Converting to \(N(0)\int_{-\hbar\omega_D}^{\hbar\omega_D}(\xi-\sqrt{\xi^2+\Delta^2})\,d\xi+N(0)\Delta^2/(N(0)V)\), evaluating the integral for \(\Delta\ll\hbar\omega_D\) gives \(-\tfrac12N(0)\Delta^2[\,1-\ln(\cdots)\,]\); using the gap equation \(1/N(0)V=\ln(2\hbar\omega_D/\Delta_0)\) to cancel the log term leaves \(E_s-E_n=-\tfrac12N(0)\Delta_0^2\). Numerically for Al (\(N(0)\sim10^{47}\,\text{J}^{-1}\text{m}^{-3}\), \(\Delta_0\sim0.18\,\text{meV}\)) this is a tiny \(\sim1\,\mu\text{eV per atom}\), consistent with the fragility of superconductivity. - A superconductor has \(\Theta_D=275\,\text{K}\) and \(N(0)V=0.25\). Compute \(T_c\) and \(\Delta_0\).
Solution
\(T_c=1.13\times275\times e^{-1/0.25}=1.13\times275\times e^{-4}=1.13\times275\times0.0183=5.69\,\text{K}\). Then \(\Delta_0=1.76\,k_BT_c=1.76\times8.617\times10^{-5}\times5.69\,\text{eV}=8.6\times10^{-4}\,\text{eV}=0.86\,\text{meV}\). - Verify the universal ratio: from \(\Delta_0=2\hbar\omega_D e^{-1/N(0)V}\) and \(k_BT_c=(2e^{\gamma}/\pi)\hbar\omega_D e^{-1/N(0)V}\), obtain \(2\Delta_0/k_BT_c\) numerically (\(\gamma=0.5772\)).
Solution
\(\dfrac{2\Delta_0}{k_BT_c}=\dfrac{2\cdot2\hbar\omega_D e^{-1/N(0)V}}{(2e^{\gamma}/\pi)\hbar\omega_D e^{-1/N(0)V}}=\dfrac{4}{2e^{\gamma}/\pi}=\dfrac{2\pi}{e^{\gamma}}\). With \(e^{0.5772}=1.781\), this is \(2\pi/1.781=6.283/1.781=3.528\). The exponentials and all material parameters cancel, which is the origin of the universality. - Near \(T_c\), expand the gap equation to show \(\Delta(T)\propto\sqrt{1-T/T_c}\) and find the coefficient.
Solution
Subtract the \(T_c\) equation (\(\Delta=0\)) from the finite-\(\Delta\) equation and expand the integrand to \(O(\Delta^2)\). The temperature-derivative term gives \(\ln(T_c/T)\approx1-T/T_c\) on the left, while the \(\Delta^2\) correction produces the coefficient \(\frac{7\zeta(3)}{8\pi^2}(\Delta/k_BT_c)^2\) from \(\sum_n(2n+1)^{-3}=\tfrac{7}{8}\zeta(3)\). Equating gives \(\Delta(T)=k_BT_c\sqrt{\dfrac{8\pi^2}{7\zeta(3)}}\sqrt{1-T/T_c}\). With \(\zeta(3)=1.202\), the prefactor is \(\sqrt{8\pi^2/(7\times1.202)}=\sqrt{9.38}=3.06\), so \(\Delta(T)\approx3.06\,k_BT_c\sqrt{1-T/T_c}\), the classic mean-field square-root onset.